11 lines
201 B
JavaScript
11 lines
201 B
JavaScript
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const filtered = []
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for (let i = 0; i < projected.length; ++i) {
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const tile = layer.tile(projected[i])
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if ([1, 2, 3, 4, 6].includes(tile)) {
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filtered.push(projected[i])
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}
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}
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return filtered
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